求调,玄关
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求调,玄关
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Sizeof_cpp楼主2024/9/24 13:18
#include<bits/stdc++.h>
using namespace std;
int b[1001],a[1001],n,m;
string s;
int main(){
	cin>>n>>m;
	for(int i=1;i<=m;i++){
		cin>>b[i]>>s[i];
		if(s[i]=='M'&&a[b[i]]==0){
			cout<<"Yes"<<endl;
			a[b[i]]=1;
		}
		else cout<<"No"<<endl;
	}
}

莫名RE

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2024/9/24 13:18
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