求助,样例输出0
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求助,样例输出0
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Zhangyijin1023楼主2024/9/23 23:10
#include<bits/stdc++.h>
using namespace std;
const int mod=998244353;
long long n,m,k,v[105],f[135][35][35][35],mul[35],mulp[35],p[35][35];
long long pow_(long long a,long long b){
	long long ans=1;
	while(b){
		if(b&1){
			ans=ans*a%mod;
		}
		a=a*a%mod;
		b/=2;
	}
	return ans%mod;
}
int check(int x){
	int cnt=0;
	while(x){
		if(x&1){
			cnt++;
		}
		x/=2;
	}
	return cnt;
}
long long count_c(long long n,long long m){
	if(!m){
		return 1;
	}
	if(n<m){
		return 0;
	}
	return mul[n]%mod*mulp[m]%mod*mulp[n-m]%mod;
}
int main(){
	scanf("%lld %lld %lld",&n,&m,&k);
	for(int i=0;i<=m;i++){
		scanf("%lld",&v[i]);
		p[i][0]=1;
		for(int j=1;j<=n;j++){
			p[i][j]=p[i][j-1]*v[i];
		}
	}
	mul[1]=1;
	mulp[1]=1; 
	for(int i=2;i<=n;i++){
		mul[i]=mul[i-1]*i;
		mulp[i]=pow_(mul[i],mod-2);
	}
	f[0][0][0][0]=1;
	for(int i=0;i<=m;i++){
		for(int j=0;j<=n;j++){
			for(int x=0;x<=k;x++){
				for(int y=0;y<=n/2;y++){
					for(int z=0;z<=n-j;z++){
						f[i+1][j+z][x+(z+y)%2][(z+y)/2]=(f[i+1][j+z][x+(z+y)%2][(z+y)/2]+f[i][j][x][y]*p[i][z]%mod*count_c(n-j,z)%mod)%mod;
					}
				}
			}
		}
	}
	long long ans=0;
	for(int i=0;i<=k;i++){
		for(int j=0;j<=n/2;j++){
			if(i+check(j)<=k){
				ans=(ans+f[m+1][n][i][j])%mod;
			}
		}
	}
	printf("%lld",ans);
	return 0;
}

调了一晚上,感觉什么问题也没有,样例一直输出0

2024/9/23 23:10
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