打表怎么只对了一个测试点(要不就是我眼瞎)
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打表怎么只对了一个测试点(要不就是我眼瞎)
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学不会图论的原神玩家楼主2023/3/2 22:51

各位大佬请问为啥我过不了呢?

#include<bits/stdc++.h>
using namespace std;
int n;
string k;
string n1[10]={"XXX","..X","XXX","XXX","X.X","XXX","XXX","XXX","XXX","xxx"}; 
string n2[10]={"X.X","..X","..X","..X","X.X","X..","X..","..X","X.X","x.x"};
string n3[10]={"X.X","..X","XXX","XXX","XxX","XXX","XXX","..X","XxX","xxx"};
string n4[10]={"X.X","..X","X..","..X","..X","..X","X.X","..X","X.X","..x"};
string n5[10]={"XXX","..X","XXX","XXX","..X","XXX","XXX","..X","XXX","xxx"};
int main()
{
	cin>>n>>k;
	for(int i=0;i<n;i++)
	{
		if(i-n<-1)
		cout<<n1[k[i]-'0']<<".";
		else
		cout<<n1[k[i]-'0'];
	}
	cout<<endl;
	for(int i=0;i<n;i++)
	{
		if(i-n<-1)
		cout<<n2[k[i]-'0']<<".";
		else
		cout<<n2[k[i]-'0'];
	}
	cout<<endl;
	for(int i=0;i<n;i++)
	{
		if(i-n<-1)
		cout<<n3[k[i]-'0']<<".";
		else
		cout<<n3[k[i]-'0'];
	}
	cout<<endl;
	for(int i=0;i<n;i++)
	{
		if(i-n<-1)
		cout<<n4[k[i]-'0']<<".";
		else
		cout<<n4[k[i]-'0'];
	}
	cout<<endl;
	for(int i=0;i<n;i++)
	{
		if(i-n<-1)
		cout<<n5[k[i]-'0']<<".";
		else
		cout<<n5[k[i]-'0'];
	}
	return 0;
}

2023/3/2 22:51
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