#include<iostream>
#include<cstring>
#include<cmath>
#include<cstdlib>
using namespace std ;
int main()
{
	int n ;
	char condition ;			//记录判断进行运算 
	scanf("%d",&n);
	getchar();
	string space = " ";
	for(int i = 0 ; i < n ; i++)
	{
		int changdu = 0 ;		//最终结果长度 
		string word ;			//输入的字符串 
		getline(cin,word);
		if(word[0] >='a' && word[0] <='c' )
		{
			condition = word[0] ;
			word.erase(0,2);
		}									//去掉英文符号 
		changdu = word.length() + 1;	//把含等号左边的长度先算一下 
		int a = 0 , b = 0 ;		//a为第一个数字，b为第二个 
		int index = word.find(space);			//寻找中间的空格下标 
		string abc = word.substr(0,index);		//截取字符串数字a 
		a = atoi(abc.c_str());
		if(a < 0 )				//负数长度就+1 
		{
			changdu++;
		}
		abc = word.substr(index,word.length());		//截取字符串数字b 
		b = atoi(abc.c_str());
		if(b < 0)				//负数长度就+1 
		{
			changdu++;
		}
		int sum = 0 ;
	//	printf("%c %d %d",condition,a,b); 
		switch(condition)				//依据字母来判断运算 
		{
			case 'a' :sum=a+b;printf("%d+%d=%d",a,b,sum);break;
			case 'b' :sum=a-b;printf("%d-%d=%d",a,b,sum);break;
			case 'c' :sum=a*b;printf("%d*%d=%d",a,b,sum);break;
		}
		if(sum < 0)changdu++;
		while(sum != 0)			//求等号位数 
		{
			sum /= 10 ;
			changdu++;
		}
		printf("\n%d\n",changdu);
	}
}