• Replace activated edge for point $(r, c)$ . That is if the edge to the point $(r+1, c)$ is activated, then instead of it, the edge to the point $(r+1, c+1)$ becomes activated, otherwise if the edge to the point $(r+1, c+1)$ , then instead if it, the edge to the point $(r+1, c)$ becomes activated. This action increases the cost of the path by $1$

• 改变激活性。例如，您可以将本来到 $(r+1,c)$ 的激活边去激活并使得到 $(r+1,c+1)$ 的边被激活。这个操作花费 $1$ 的代价。

otherwise 后面的部分翻译少了。