#define _CRT_SECURE_NO_DEPRECATE
#include<bits/stdc++.h>
using namespace std;
int jug = -1;
string s1, s2, mi;
string sb[26] = { "A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
int a[26], b[26];
int main()
 {
	cin >> s1 >> s2 >> mi;
	for (int i = 0; i < s1.length(); i++)
	{
			a[s1[i] - 'A'] = s2[i] - 'A';
			if (b[s1[i] - 'A'] == 0)//如果这个字母还没被解密过,b[]数组
			{
			  b[s1[i] - 'A'] = s2[i] - 'A' + 1;
			}
			else {
				if (s2[i] - 'A' != b[s1[i] - 'A'] - 1)
				{
					jug = 0;
					break;//有不一样的直接润,第三种情况
				}
			}	
	}
	for (int i = 0; i < 26; i++)
	{
		if (b[i] == 0) {
			jug = 0;
			break;
		}
	}//检测是否26个字母都有
	if (jug == 0)
	{
		cout << "Failed";
	}
	else {
		for (int i = 0; i < mi.length(); i++)
		{
			cout << sb[a[mi[i] - 'A']];
		}
	}
}