评测记录

基本思路:

一直输出1 -1直到没有1或-1，再连续输出1或-1.

蒟蒻代码

#include <cstdio>
#define m10(x) ((x << 3) + (x << 1))
#define r0 putchar(49), putchar(32)
#define r1 putchar(45), r0

using namespace std;
int n, num[2] = {0, 0};

inline int qread()
{
    int ot = 0, t = getchar();
    while (t < 48 || t > 57)
        t = getchar();
    while (t >= 48 && t <= 57)
    {
        ot = m10(ot) + t ^ 48;
        t = getchar();
    }
    return ot;
}

inline void read()
{
    register int f = 0, t = getchar();
    while (t != 49)
    {
        if (t == 45)
            f = 1;
        t = getchar();
    }
    ++num[f];
    return;
}

int main()
{
    n = qread();
    while (n)
        --n, read();
    while (num[0] && num[1])
    {
        --num[0], --num[1];
        r0, r1;
    }
    while (num[0])
        --num[0], r0;
    while (num[1])
        --num[1], r1;
    return 0;
}