样例过了

#include <iostream>
using namespace std;

const int N = 5e3 + 9;
int l, n, a[N];

int main() {
	scanf("%d %d", &l, &n);
	for (int i = 1; i <= n; ++i)
		scanf("%d", &a[i]);

    int min = 0, max = 0;
    for (int i = 1; i <= n; ++i) {
        if (i <= n / 2) { min += i; max += n - i + 1; }
        else { min += n - i + 1; max += i; }
    }
    cout << min << " " << max << endl;
    return 0;
}