附代码，#2、4、6、10运算超时，其余正确，得分60

a = map(int,input().split())
list_1 = list(a)
n = list_1[0]
x = list_1[1]
m = 0
if  1<= n <= 10**6 and 0<=x <= 9:#限制输入值大小
    for i in range (1,n+1):#建立一个范围，从1输出到n+1
        for b in str(i):#遍历范围内的每一个输出，对比x
            if str(x) == b:#符合要求，m+=1
                m+=1
    print(m)#返回m值，即字符出现次数