样例都没过，求调qwq

指导我调出来的悬赏关注awa

#pragma GCC target("sse3","sse2","sse")
#pragma GCC target("avx","sse4","sse4.1","sse4.2","ssse3")
#include<bits/stdc++.h>
using namespace std;
#define reg register
#define inf 0x7ffffff
#define IT set<node>::iterator
#define int long long
typedef long long TYPE;
struct node{
	unsigned int l,r;
	mutable TYPE v;
	node(unsigned int left,unsigned int right=0,TYPE value=0);
};
bool operator<(node a,node b){
	return a.l<b.l;
}
node::node(unsigned int left,unsigned int right,TYPE value){
	l=left;
	r=right;
	v=value;
}
struct node2{
	unsigned int l,r;
	mutable TYPE v;
	node2(unsigned int left,unsigned int right=0,TYPE value=0);
};
bool operator<(node2 a,node2 b){
	return a.v<b.v;
}
node2::node2(unsigned int left,unsigned int right,TYPE value){
	l=left;
	r=right;
	v=value;
}
set<node>odt; 
inline IT split(unsigned int p){
	IT it=odt.lower_bound(node(p));
	if(it!=odt.end()&&it->l==p)
		return it;
	--it;
	unsigned r=it->r,l=it->l;
	TYPE v=it->v;
	odt.erase(it);
	odt.insert(node(l,p-1,v));
	return odt.insert(node(p,r,v)).first;	
}
inline void assign(int l, int r, int v) {
	IT itr=split(r+1),itl=split(l);
	odt.erase(itl, itr);
	odt.insert(node(l, r, v));
}
inline int qpow(long long a,long long b,long long c){
    reg int ans=1,tmp=a;
    tmp%=c;
    while(b){
        if(b&1)ans=ans*tmp%c;
        tmp=tmp*tmp%c;
        b>>=1;
    }
    return ans%c;
}
inline void add(int l,int r,int v){
	IT itr=split(r+1),itl=split(l);
	for(IT it=itl;it!=itr;++it)
		it->v+=v;
}
inline int query1(int l,int r,int x){
	IT itr=split(r+1),itl=split(l);
	vector<node2>v;
	v.clear();
	int cnt=0;
	for(IT it=itl;it!=itr;++it)
		v.push_back(node2(it->l,it->r,it->v));
	sort(v.begin(),v.end());
	vector<node2>::iterator it2=v.end();
	for(vector<node2>::iterator it1=v.begin();it1!=it2;++it1){
		cnt+=it1->r-it1->l+1;
		if(cnt>=x)return it1->v;
	}
}
inline unsigned long long query2(long long l,long long r,long long x,long long y){
	IT itr=split(r+1),itl=split(l);
	unsigned long long ans=0;
	for(IT it=itl;it!=itr;++it)
		ans+=(itr->r-itl->l+1)*qpow(it->v,x,y)%y;
	return ans;	
}
namespace IO{
	char ibuf[(1<<20)+1],*iS,*iT;
	#if ONLINE_JUDGE
		#define gh() (iS==iT?iT=(iS=ibuf)+fread(ibuf,1,(1<<20)+1,stdin),(iS==iT?EOF:*iS++):*iS++)
 	#else
		#define gh() getchar()
	#endif
	inline long long read(){
		reg char ch=gh();
		reg long long x=0;
		reg char t=0;
		while(ch<'0'||ch>'9')   t|=ch=='-',ch=gh();
		while(ch>='0'&&ch<='9') x=(x<<1)+(x<<3)+(ch^48),ch=gh();
		return t?-x:x;
	}
	inline void write(long long x) {
		if(x<0)
			putchar('-'), x = -x;
		if(x>9)
			write(x/10);
		putchar(x%10+'0');
	}
}
using IO::read;
using IO::write;
int n,m,s,v;
inline int rnd(){
	int ret=s;
	s=(s*7+13)%1000000007;
	return ret;
}
signed main(){
	n=read();
	m=read();
	s=read();
	v=read();
	for(int i=1;i<=n;++i){
		static int tmp=0;
		tmp=rnd()%v+1;
		odt.insert(node(i,i,(long long)tmp));
	}
	odt.insert(node(n+1,n+1,0));
	for(int i=1;i<=m;++i){
		static int l=0,r=0,x=0,y=0,op=0;
		op=rnd()%4+1;
		l=rnd()%n+1,r=rnd()%n+1;
		if(l>r)l^=r^=l^=r;
		if(op==3)x=rnd()%(r-l+1);
		else x=rnd()%v+1;
		if(op==4)y=rnd()%v+1;
		//Hello,world!
		switch(op){
			case 1:add(l,r,(long long)x);break;
			case 2:assign(l,r,(long long)x);break;
			case 3:write(query1((long long)l,(long long)r,(long long)x));putchar('\n');break;
			case 4:write(query2((long long)l,(long long)r,x,(long long)y));putchar('\n');break;
		}
	}
	return 0;
}