∫1xdx=∫x−1dx=x00+C=e0lnx0+C=1+0lnx0+C=10+lnx+C=lnx+C\displaystyle \int \frac{1}{x}dx=\int x^{-1}dx=\frac{x^0}{0}+C=\frac{e^{0\ln x}}{0}+C=\frac{1+0\ln x}{0}+C=\frac{1}{0}+\ln x+C=\ln x+C∫x1dx=∫x−1dx=0x0+C=0e0lnx+C=01+0lnx+C=01+lnx+C=lnx+C
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