蒟蒻奇异的90分求调
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蒟蒻奇异的90分求调
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SZnP楼主2022/7/1 13:55
#include <bits/stdc++.h>
using namespace std;
int main()
{
double x1,x2,s,a,b,c;
cin>>a>>b>>c;
s=b*b-4*a*c;
x1=1.0*(-b+sqrt(b*b-4*a*c))/(2.0*a);
x2=1.0*(-b-sqrt(b*b-4*a*c))/(2.0*a);
if(s<=0){cout<<"No answer!";return 0;}
if(x1==x2){printf("x1=x2=%.5lf",x1);return 0;}
if(x1>x2){printf("x1=%.5lf;x2=%.5lf",x2,x1);return 0;}
else {printf("x1=%.5lf;x2=%.5lf",x1,x2);return 0;}
return 0;
}
2022/7/1 13:55
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