这里是代码
//------------------------
//Online Judge : Luogu
//By : KS_tips_CN
//Subject :
//------------------------
//#include<bits/stdc++.h>
//#include<map>
//#include<stack>
//#include<list>
//#include<set>
#include<iostream>
#include<iomanip>
#include<cstdio>
#include<cmath>
#include<cstring>
#include<queue>
#include<algorithm>
#include<vector>
#define ll long long
#define reg register int
#define gc getchar()
#define MAXN 200
#define MOD
using namespace std;
inline ll read( void ) ;
struct per{
string name;
ll poi,value,ex,xh;
}p[MAXN];
int n;
inline bool cmp1( per a , per b ){
if( a.value != b.value ) return a.value > b.value ;
else return a.xh < b.xh ;
}
inline bool cmp2( per a , per b ){
if( a.poi != b.poi ) return a.poi > b.poi ;
else if( a.ex != b.ex ) return a.ex > b.ex ;
else return a.xh < b.xh ;
}
int main( void ) {
n = read();
string s ;
for( reg i = 1 ; i <= n ; i++ ){
p[i].xh = i;
cin >> p[i].name >> s ;
if( s == "BangZhu" ) p[i].poi = 7;
else if( s == "FuBangZhu" ) p[i].poi = 6;
else if( s == "HuFa" ) p[i].poi = 5;
else if( s == "ZhangLao" ) p[i].poi = 4;
else if( s == "TangZhu" ) p[i].poi = 3;
else if( s == "JingYing" )p[i].poi = 2;
p[i].value = read();
p[i].ex = read();
}
cout << endl;
//现在我们已经存好了所有玩家的所有资料
sort(p+1,p+1+n,cmp1);
//现在已经将所有玩家按照帮贡进行排序了
int qwe = 0;
for( reg i = 1 ; i <= n ; i++ ){
if( p[i].poi >= 6 ) continue;
//跳过帮主和副帮主
qwe++;
if( qwe <= 2 ) p[i].poi = 5 ;
else if( qwe <= 6 ) p[i].poi = 4;
else if( qwe <= 13 ) p[i].poi = 3;
else if( qwe <= 28 ) p[i].poi = 2;
}
sort( p+1,p+1+n,cmp2);
for( reg i = 1 ; i <= n ; i++ ){
cout << p[i].name << ' ';
if( p[i].poi == 7 ) printf("BangZhu ");
else if( p[i].poi == 6 ) printf("FuBangZhu ");
else if( p[i].poi == 5 ) printf("HuFa ");
else if( p[i].poi == 4 ) printf("ZhangLao ");
else if( p[i].poi == 3 ) printf("TangZhu ");
else if( p[i].poi == 2 ) printf("JingYing ");
cout << p[i].ex << endl ;
}
return 0;
}
inline ll read( void ) {
ll x = 0 , f = 0 ;
char ch = gc ;
while( !isdigit( ch ) )
f |= ( ch == '-' ) , ch = gc ;
while( isdigit( ch ) )
x = ( x << 1 ) + ( x << 3 ) + ( ch ^ 48 ) , ch = gc ;
return f ? -x : x ;
}