#include<iostream>
#include<cmath>
using namespace std;

int main(){
    string s; getline(cin,s);
    int r;
    string s1 = "";
    for(int i = 0; i <= s.size()-1; i++){
        if(s[i] != ' ') s1 += s[i];
    }
    int op,w,d;
    char p;
    for(int i = 0; i <= s1.size()-1; i++){
        if(s1[i] == '+' || s1[i] == '-') {op = i;p = s1[i];}
        if(s1[i] == '?'){w = i;}
        if(s1[i] == '='){d = i;}
    }
    if(d < w){
        int x = 0, y = 0;
        for(int i = 0; i <= op - 1; i++){x *= 10; x += s1[i]-'0';}
        for(int i = op + 1; i < d; i++){y *= 10; y += s1[i]-'0';}
        if(p == '+') cout << x + y;
        else cout << x - y;
    }
    else if(op < w){
        int x = 0, y = 0;
        for(int i = 0; i <= op - 1; i++){x *= 10; x += s1[i]-'0';}
        for(int i = d + 1; i < s1.size(); i++){y *= 10; y += s1[i]-'0';}
        if(p == '+') cout << y - x;
        else cout << x - y;
    }
    else{
        int x = 0, y = 0;
        for(int i = op + 1; i <= d - 1; i++){x *= 10; x += s1[i]-'0';}
        for(int i = d + 1; i < s1.size(); i++){y *= 10; y += s1[i]-'0';}
        if(p == '+') cout << y - x;
        else cout << x + y;
    }
} 

思路是先去掉空格再识别符号、等号、？，然后根据这三个的位置去算，样例全都过了，但只有50分