Py3 90分求指点
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Py3 90分求指点
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Joker_1212楼主2022/5/3 18:38

代码如下:

K = int(input())
flag = 1
for i in range(1, 3):
    for j in range(10):
        for k in range(10):
            if (100 * i + 10 * j + k) % K == 0:
                for m in range(10):
                    if (100 * j + 10 * k + m) % K == 0:
                        for n in range(10):
                            if (100 * k + 10 * m + n) % K == 0:
                                print(i, j, k, m, n, sep='')
                                flag = 0

if 300 % K == 0:
    print(30000)

if flag:
    print("No")

#9WA

2022/5/3 18:38
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