#include <iostream>
using namespace std;

int n, a[105][10], count = 0;
char c;

int main()
{
	cin >> n;
	for(int i = 1; i <= n; i++)
	{
		for(int j = 1; j <= 4; j++)
		{
			c = getchar();
			a[i][j] = (int)(c - 48);
		}
		getchar();
		if(a[i][4] - a[i][1] - a[i][2] - a[i][3] > 0)
			count++;
	}
	cout << count << endl;
	return 0;
}

用字符读每一位存进二维数组里面，为啥不对