TLE 了
#include <iostream>
#include <cstring>
#include <algorithm>
using namespace std;
const int N = 1e5 + 5;
int n, m, x, y, k, a[N], opt;
struct Node
{
int s[2], p, v;
int size, sum;
int flag;
void init(int _v, int _p)
{
flag = 0;
sum = v = _v, p = _p;
size = 1;
}
}tr[N];
int root, idx;
void pushup(int x)
{
// TODO: 利用子节点信息维护当前节点信息
tr[x].sum = tr[tr[x].s[0]].sum + tr[tr[x].s[1]].sum + tr[x].v;
tr[x].size = tr[tr[x].s[0]].size + tr[tr[x].s[1]].size + 1;
}
void pushdown(int x)
{
// TODO: 将懒标记下传
int k = tr[x].flag;
tr[x].flag = 0;
int u = tr[x].s[0];
if(u){
tr[u].flag += k;
tr[u].v += k;
tr[u].sum += tr[u].size * k;
}
u = tr[x].s[1];
if(u){
tr[u].flag += k;
tr[u].v += k;
tr[u].sum += tr[u].size * k;
}
}
void rotate(int x) // 旋转
{
int y = tr[x].p, z = tr[y].p;
int k = tr[y].s[1] == x;
tr[z].s[tr[z].s[1] == y] = x, tr[x].p = z;
tr[y].s[k] = tr[x].s[k ^ 1], tr[tr[x].s[k ^ 1]].p = y;
tr[x].s[k ^ 1] = y, tr[y].p = x;
pushup(y), pushup(x);
}
void splay(int x, int k) // splay操作
{
while (tr[x].p != k)
{
int y = tr[x].p, z = tr[y].p;
if (z != k)
if ((tr[y].s[1] == x) ^ (tr[z].s[1] == y)) rotate(x);
else rotate(y);
rotate(x);
}
if (!k) root = x;
}
int build(int l, int r, int p){
int t = ++ idx;
if(l == r)
tr[t].init(a[l], p);
else if(l == r - 1){
tr[t].init(a[r], p);
tr[t].s[0] = build(l, l, t);
}
else{
int mid = (l + r) / 2;
tr[idx].init(a[mid], p);
tr[idx].s[0] = build(l, mid - 1, t);
tr[idx].s[1] = build(mid + 1, r, t);
}
pushup(t);
return idx;
}
int get_k(int k){
int u=root;
while(true){
pushdown(u);
if(tr[tr[u].s[0]].size>=k)u=tr[u].s[0];
else if(tr[tr[u].s[0]].size+1==k)return u;
else k-=tr[tr[u].s[0]].size+1,u=tr[u].s[1];
}
return -1;
}
int main()
{
cin >> n >> m;
for (int i = 1; i <= n; i ++ )
cin >> a[i];
root = build(0, n + 1, 0);
while (m -- ){
cin >> opt;
if(opt == 1){
cin >> x >> y >> k;
int L = get_k(x - 1), R = get_k(y + 1);
splay(L, 0),splay(R, L);
int u = tr[R].s[0];
tr[u].flag += k;
tr[u].v += k;
tr[u].sum += tr[u].size * k;
pushup(L);
}
else{
cin >> x >> y;
int L = get_k(x - 1), R = get_k(y + 1);
splay(L, 0),splay(R, L);
cout << tr[tr[R].s[0]].sum << endl;
}
}
return 0;
}